An experiment shows that 13.88g of Calcium choride were obtained from the combination of 5g of Ca with chlorine what is the empirical formula of the compound?

CaCl₂

Explanation:

Mass of Calcium chloride  = 13.88g

Mass of Ca = 5g

So,

Mass of chlorine  = 13.88g - 5g  = 8.88g

Now;

Empirical formula of the compound;

 The empirical formula is the simplest formula of a compound;

                                               Elements

                               Ca                                       Cl

Mass                       5                                        8.88

Number of

moles                    5/40                                  8.88/35.5

                             0.125                                   0.25

Divide by

the smallest        0.125/0.125                          0.25/0.125

                                    1                                            2

The empirical formula of the compound is CaCl₂

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

the answer is true. hope it .