A mixture contains 21.7 g NaCI, 3.74 g KCI, and 9.76 g Lici. What is the mole fraction of NaCl in this mixture? Molar mass
NaCl: 58.44g/mol
KCl: 74.55g/mol
LiCl: 42.39g/mol

Mole Fraction of NaCl=0.5697

Explanation:

No OF Moles of NaCl=  Mass / Molar mass

=21.7 g/58.44g/mol

=0.371moles

No OF Moles of KCl=  Mass / Molar mass

=3.74g/74.55g/mol

=0.0502moles

No OF Moles of LiCl=  Mass / Molar mass

=9.76 g/42.39g/mol

=0.230moles

Mole Fraction of NaCL = Moles of NaCL/ Total number of moles of the mixture

=0.371/( 0.371+ 0.0502+0.230)

0.371/0.6512

=0.5697

Mole fraction: 0.570

Explanation:

Mole fraction is defined as the ratio of moles of a compound in a mixture over the total moles of the mixture. To solve this problem, we need to find moles of the 3 salts:

Moles NaCl -Molar mass: 58.44g/mol-:

21.7g NaCl * (1mol / 58.44g) = 0.3713 moles

Moles KCl -Molar mass: 74.55g/mol-:

3.74g KCl * (1mol / 74.55g) = 0.0502 moles

Moles LiCl -Molar mass: 42.394g/mol-:

9.76g LiCl * (1mol / 42.394g) = 0.2302 moles

Mole fraction NaCl:

0.3713mol / (0.3713mol + 0.0502mol + 0.2302mol) =

0.570

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.