A flask containing a volume of 180 L of bromine was collected under a pressure of 35.5 kPa. What pressure would have been required for the volume of the gas to have been 80.0 L, assuming the same temperature? Which gas law did you need to use?

P₂ = 80 KPa

Boyle's law is applied.

Explanation:

Given data:

Initial volume = 180 L

Initial pressure = 35.5 KPa

Final pressure = ?

Final volume = 80.0 L

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

35.5 KPa × 180 L = P₂ × 80.0 L

P₂ = 6390 KPa. L/ 80.0 L

P₂ = 80 KPa

u i forgot the answer?

i think slash and