A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and it weighs 0.941g . Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Round your answer to 3 significant digits.

the  molar mass of the compound is  34.0 g /mol

Explanation:

The computation of the molar mass of the compound is as follows:

As we know that

PV = nRT

n = mass ÷ MW

PV = mRT ÷ MW

It can be rearrange as

MW = mRT ÷ (PV)

MW = (0.941)(0.082)(150 + 273) ÷ (1 × 0.96)

= 33.99g/mol

= 34.0 g /mol

Hence, the  molar mass of the compound is  34.0 g /mol