the si unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the cesium atom. calculate the wavelength of this radiation (to three significant figures).

Given:

Radiation emission in Cs atom = 9,192,632,770 cycles

To determine:

The wavelength of the above radiation

Explanation:

It is given that :-

1 sec equivalent to 9,192, 631, 770

Now, frequency (ν) = cycles /sec = 9,192, 631, 770/sec

Wavelength of a radiation is given as:

λ = c/ν

where c = speed of light = 3*10⁸ m/s

λ = 3*10⁸ ms⁻¹/9,192, 631, 770 s⁻¹ = 0.0326 m

Ans: Thus the wavelength of this radiation is 0.033 m

i had this on my unit activity, i can you if you are a plato student. are you a plato student?

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.