What is the energy of a photon (J) that has a wavelength of 105 nm?

E = 1.89×10⁻¹⁹ J

Explanation:

Given data:

Wavelength of photon = 105 nm (105 ×10⁻⁹ m)

Energy of photon = ?

Solution:

Formula:

E = hc/λ

h = plancks constant = 6.63×10⁻³⁴ Js

c = speed of wave = 3×10⁸ m/s

by putting values,

E =  6.63×10⁻³⁴ Js ×3×10⁸ m/s / 105 ×10⁻⁹ m

E = 19.89×10⁻²⁶ J.m / 105 ×10⁻⁹ m

E = 0.189×10⁻¹⁷ J

E = 1.89×10⁻¹⁹ J

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).