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120 moles of Mg

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Mg + 2H₃PO₄ —> Mg₃(PO₄)₂ + 3H₂

From the balanced equation above,

3 moles of Mg reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of Mg needed to produce 120 moles of H₂. This can be obtained as follow:

From the balanced equation above,

3 moles of Mg reacted to produce 3 moles of H₂.

Therefore, 120 moles of Mg will also react to produce 120 moles of H₂.

Thus, 120 moles of Mg is needed for the reaction.

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