How much HCl exists in 347 mL of 0.48 M
solution of HCI?
Answer in units of mol.

Number of moles of HCl = 0.17 mol

Explanation:

Given data:

Volume of solution = 347 mL

Molarity of solution = 0.48 M

Number of moles of HCl present = ?

Solution:

Formula:

Molarity = number of moles of HCl / volume in L

Volume in L:

347 mL× 1L / 1000 mL

0.347 L

by putting values in formula:

0.48 mol/L = number of moles / 0.347 L

Number of moles = 0.48 mol/L × 0.347 L

Number of moles = 0.17 mol

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