The temperature of a reaction vessel with liquid reactants is lowered to one-third of the original temperature. What will happen to the rate of the reaction? A) It will increase because fewer particles will have the required activation energy.
B) It will decrease because fewer particles will have the required activation energy.
C) It will increase because surface area of the particles will increase.
D) It will decrease because surface area of the particles will increase.

B) It will decrease because fewer particles will have the required activation energy.

Explanation:

Temperature is one of the important factors that affect the rate of a chemical reaction. An increase in the temperature of a reaction will cause the reactants to gain more kinetic energy and hence, reduce the energy required for reactants collision (start) to occur i.e. activation energy.

Note that, once the activation energy is reduced, the rate of reaction is increased. In this case, the temperature of a reaction vessel with liquid reactants is lowered to one-third (1/3) of the original temperature. Due to a reduction in the reaction's temperature, the rate of reaction will also decrease because fewer particles will have the required activation energy.

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

its b it was a compound