A 100 gram sample of naturally occurring boron contains 19.78 % of B-10 and 80.22 % of B-11. Which numerical setup can be used to determine the atomic mass of naturally occurring B

The required numerical set up is;

RAM = (19.78% * 10) + (80.22% * 11)

Explanation:

The relative atomic mass is the sum of the products of the mass of each isotope and its relative abundance.

Hence the relative atomic mass of Boron is obtained form;

RAM = (19.78% * 10) + (80.22% * 11)

RAM = (1.978) + (8.8242)

RAM =10.8022

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