A. 207 kJ
B. 4730 kJ
C. 9460 kJ
D. 414 kJ

Explanation:

The formula we must use is given to us:

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

Now we know:

Substitute the values into the formula.

Multiply. Note that the kilograms (kg) will cancel each other out.

9460 kilojoules are required to vaporize 2 kilograms of copper.

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it means there are 3 atoms of oxygen