10 The reaction in which ammonia is formed is N2(g) + 3H2(g) + 2NH3(). At equilibrium, a
1-L flask contains 0.15 mol H. 0.25 mol N, and 0.10 mol NH. Calculate K., for the reaction.
11.85
23.8
25.0
16

The equilibrium constant (K) : 11.85

Given

Reaction

N₂(g) + 3H₂(g) ⇒ 2NH₃(g)

Required

K(equilibrium constant)

Solution

The equilibrium constant (K) is the value of the concentration product in the equilibrium

The equilibrium constant based on concentration (K) in a reaction  

pA + qB -----> mC + nD  

For the reaction above :

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !