How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid? H2SO4(aq) + NaOH(aq) = 2H2O(L) + Na2SO4(aq)

Select one:
a. 46.2 moles NaOH
b. 11.6 moles NaOH
c. 5.78 moles NaOH
d. 23.1 moles NaOH

46.2 moles of NaOH are required.

Explanation:

Given data:

Moles of NaOH required = ?

Moles of H₂SO₄ = 23.1 mol

Solution:

Chemical equation:

H₂SO₄ + 2NaOH         →       2H₂O + Na₂SO₄

Now we will compare the moles of NaOH with H₂SO₄.

              H₂SO₄         :            NaOH

                1                :                2

             23.1              :        2×23.1 = 46.2

Thus, 46.2 moles of NaOH are required.