Chemistry, 01.01.2021 14:00 yoyo4396

You are a scientist working on increasing the efficiency of appliances to waste less electricity. You are running experiments measuring the input, output, and waste energy
from 3 light bulbs. Given the data below, determine which model has the lowest
percentage of energy lost as waste.
Lightbulb 1: 200 joules in, 50 joules wasted, 150 joules out
Lightbulb 2: 100 joules in, 30 joules wasted, 70 joules out
Lightbulb 3: 150 joules in, 100 joules wasted, 50 joules out

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Answer from: quanharris2k19

Lightbulb 1 has the lowest percentage of energy lost as waste : 25%

Further explanation

Given

The input, output, and waste energy of Lightbulb

Required

The lowest percentage of energy lost as waste.

Solution

Lightbulb 1 :

$\tt \%energy~lost=\dfrac{50}{200}\times 100\%=25\%$

Lightbulb 2 :

$\tt \%energy~lost=\dfrac{30}{100}\times 100\%=30\%$

Lightbulb 3:

$\tt \%energy~lost=\dfrac{100}{150}\times 100\%=66.7\%$

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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