A sample of water is heated from 10 °C to 50 °C using 286 J of energy. What is the mass of water that was heated? help

Mass of water == 1.71 g

Explanation:

Given data:

Initial temperature of water = 10°C

Final temperature of water = 50°C

Energy absorbed = 286 J

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  50°C -  10°C

ΔT = 40°C

by putting  values,

286 J = m × 4.18 J/g.°C × 40°C

286 J = m × 167.2 J/g

m = 286 J / 167.2 J/g

m = 1.71 g

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.