Calculate the volume of oxygen at NTP obtained by decomposing 12.26g of KCLO3(at wt. K=39.1, Cl=35.5 and O = 16)

3.61 L

Explanation:

To calculate the moles, we use the equation:

2 moles of    produce = 3 moles of  

0.1 moles of   produce = moles of    

According to the ideal gas equation:'

P = Pressure of the gas = 1 atm (NTP)

V= Volume of the gas = ?

T= Temperature of the gas = 20°C = (20+273) K = 293 K    (NTP)

R=  Value of gas constant in in kilopascals = 0.0821 Latm/K mol

Thus volume of oxygen at NTP obtained by decomposing 12.26 g of   is 3.61 L

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