a piece of tin foil has a volume of 0.645 ml to the 3rd if a piece measures 10.0 mm by 12.5 m what is the thickness of the foil

Explanation:

Fundamentally the aluminum foil is a rectangular prism. It has a length, a width, and a thickness.

The volume of a rectangular prism is expressed as

If we know the volume and two of the three dimensions, we can rearrange the equation to solve for the thickness.

But we should also be sure to confirm our units.

A liter is defined as 1000 cm^3. Therefore a mL is equal to 1 cm^3.

You should convert the units of measure given in the problem statement such that the units are aligned. For example, 10.0mm will be 1 cm and 12.5m will be 1250 cm. This will give you a height in cm.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.