How many grams of MgO are produced from the complete reaction of 94.2 g Mg?

157 g of MgO

Explanation:

the reaction:

2Mg + O2 ➡️ 2MgO

1) find the mol of Mg

mol = mass / molar mass

mass = 94.2 g

molar mass = 24

mol = 94.2 / 24

mol = 3.925 mol

2 mol = 3.925 moles

2) find mass of MgO

mass = mol × molar mass

mol = 3.925

molar mass = 24+16 = 40

mass = 3.925 × 40

= 157 g

sry but any answer choices

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