Watch the scenario to answer the question below. 2.What happened with the canned drink?
A. The sand gained energy released by the cold canned drink.
B. The sand released energy that was then gained by the cold canned drink.
C. The sand and the canned drink both had a total gain of energy.
D. The sand and the canned drink both had a total gain of energy.
E. Neither the sand nor the canned drink had a change in energy.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole