Type the correct answer in the box, Express the answer to three significant figures. Given: N2 + 3Cl2 + 2NC3, AH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in the reaction. The AH when 85.3 grams of chlorine reacts in the given reaction is kilojoules.

The given chemical reaction is:

Δ∑BE(reactants)-∑BE(products)

                = {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

                    = 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine =  

                            = 1.20 mol  

Heat change when 1.20 mol chlorine reacts

                            =

Explanation:

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the answer is c i believe