Use the following reaction: 6 NaCl + Ba3(PO4)2 → 2 Na3PO4 + 3 BaCl2

How much barium chloride is produced (in g) when 1500 g of sodium chloride react with excess barium phosphate?

Round your answer to a whole number, do not write the units.

Mass of Barium chloride produced : 2666.56 g

Given

Reaction

6 NaCl + Ba3(PO4)2 → 2 Na3PO4 + 3 BaCl2

1500 g of sodium chloride

Required

Barium chloride produced

Solution

mol NaCl (MW= 58.5 g/mol) :

mol = mass : MW

mol = 1500 g : 58.5 g/mol

mol = 25.64

mol Barium chloride-BaCl2 based on mol NaCl(as a limiting reactant)

From the equation, mol ratio NaCl : BaCl2 = 6 : 3, so mol BaCl2 :

mass BaCl2(MW=208 g/mol) :

mass = mol x MW

mass = 12.82 x 208

mass = 2666.56 g

i think that the answer is c

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.