A 10.0-liter flask contains 1.013 grams of oxygen and .572 grams of carbon dioxide at 180C. What are the partial pressures of oxygen and carbon dioxide? What is the total pressure? What is the mole fraction of oxygen in the mixture?

P tot = 0.1065 atm

The mole fraction of oxygen in the mixture : 0.709

Given

10 L flask

1.013 g O₂

572 g CO₂

T = 18 °C = 291 K

Required

P O₂ and P CO₂

Solution

Dalton Law's of partila pressure

P tot = P₁ + P₂ + ..Pₙ

From ideal gas Law :

P tot = P O₂ + P CO₂

P tot = 0.0755 + 0.031

P tot = 0.1065 atm

The mole fraction of  O₂ :

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.