The reaction of iron (III) metal with a solution of copper (II) sulfate releases iron ions into the solution through a single displacement reaction. 1. What mass of iron (in grams) is required to remove all the copper ions from a 150mL of 0.100 mol/L solution of copper (II) sulfate?
2. Determine the moles of iron ions produced in this reaction.
3. Name a soluble compound that could be added to precipitate all of the iron ions from the solution.
4. What mass of the soluble compound from part (c) is required to precipitate all of the iron ions you determined in part (b)? Give your final answer in grams.

Astudent made the lewis dot diagram of a compound as shown. mg is written with two dots shown on its top. an o is written on each side of mg. each o has six dots around it. an arrow is shown from one dot on mg toward the vacant space around the o on the right. another arrow is shown from the other dot on mg toward the vacant space around the o on the left. the title of the art is students lewis dot model. what is the error in the lewis dot diagram? an o atom should transfer all its six electrons to mg because the formula is mgo. both electrons of mg should be transferred to one o atom because the formula is mgo. the electrons should be transferred from each o atom to mg because mg has fewer electrons. the number of dots around mg should be four because it has to transfer two electrons to each o.