Consider the chemical equations shown here. 2H2(g) + O2(g) → 2H2O(g) AH, = -483.6 kJ = 2 =-241.8 kJ/mol
302(9) ► 203(9) AH2 = 284.6 kJ = 2 = 142.3 kJ/mol
What is the overall enthalpy of reaction for the equation shown below?
3H2(g) + O2(g) → 3H20 (g)
kJ

-867.7kJ

Explanation:

3H2(g)+O3(g)—>3H2O(g)=

-867.7kJ

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.