Reaction: 2 Ag2CO3 --> 4 Ag + 2 CO2 + O2, how many moles of silver will be produced when 97.4g of silver carbonate decomposes?

0.7 moles of Ag are produced

Explanation:

Given data:

Mass of silver carbonate = 97.4 g

Moles of silver produced = ?

Solution:

Chemical equation:

2Ag₂CO₃     →     4Ag + 3CO₂

Number of moles of Ag₂CO₃ :

Number of moles = mass/molar mass

Number of moles = 97.4 g/ 275.75 g/mol

Number of moles = 0.35 mol

Now we will compare the moles of Ag and Ag₂CO₃.

              Ag₂CO₃           :         Ag

                    2                :           4

                0.35              :             4/2×0.35 = 0.7

0.7 moles of Ag are produced.

well in order to answer this question you have to provide more information < 3

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.