the heat of fusion of aluminum is 95 cal/g. calculate how many grams of aluminum(already at its melting point) could be melted with 1,265,730 cal of energy (round your answer to two decimal places)

Given

Lf=latent heat of fusion  of Al = 95 cal/g

Q = 1,265,730 cal

Required

mass of Aluminium

Solution

The heat to change the phase can be formulated :

Q = m.Lf (melting/freezing)

Input the value

1,265,730 cal = m . 95 cal/g

m = 1,265,730 cal : 95 cal/g

m = 13323.47 g

a chemical reaction

explanation:

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