45 points! How much heat in Joules would it take to heat up a block of aluminum that weighs 1000.0 grams from a temperature of 70 degrees C, to it's melting point at 192.4C? specific heat for aluminum is .89 J/g-C. do not round answer- pls help

1.1 × 10⁵ J

Explanation:

Step 1: Given data

Step 2: Calculate the change in the temperature

ΔT = 192.4 °C - 70 °C = 122 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.89 J/g.°C × 1000.0 g × 122 °C

Q = 1.1 × 10⁵ J

3

explanation:

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."