Convert these plz 1. 1.29 x 10^24 atoms of HF to grams

2. 3.14g of H2O to molecules

3. 2.79g NH3 to atoms

4. 4.90 mol Al2O3 to grams. To atoms

5. 3.56g of Cu to atom

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally