10. (05.05 MC)

Read the chemical equation.

Fe2O3 + CO → Fe + CO2

If 1.8 moles of Fe2O3 react with 2.7 moles of CO, how many moles of each product are formed? (3 points)

5.4 moles Fe and 1.8 moles CO2

2.7 moles Fe and 0.9 moles CO2

3.6 moles Fe and 5.4 moles CO2

1.8 moles Fe and 2.7 moles CO2

1.8 moles Fe and 2.7 moles are produced.

Explanation:

The balanced chemical reaction is:

According to stoichiometry :

3 moles of require 1 mole of

Thus 2.7 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 3 moles of give = 2 moles of  and 3 moles of

Thus 2.7 moles of will give =  of  and  of

Thus 1.8 moles Fe and 2.7 moles are produced.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g