Calculate the maximum mass of magnesium oxide
that can be made from
2.4g of magnesium and
2.4g of oxygen.
1
1
2Mg + 0, → 2Mgo

Mass = 3 g

Explanation:

Given data:

Mass of magnesium = 2.4 g

Mass of oxygen = 2.4 g

Mass of magnesium oxide formed = ?

Solution:

Chemical equation;

2Mg + O₂    →     2MgO

Number of moles of oxygen:

Number of moles = mass / molar mass

Number of moles = 2.4 g/ 32 g/mol

Number of moles = 0.075 mol

Number of moles of magnesium:

Number of moles = mass / molar mass

Number of moles = 2.4 g/ 24 g/mol

Number of moles = 0.1 mol

now we will compare the moles of magnesium oxide with both reactant.

               Mg         :        MgO

                 2          :          2

               0.075    :        0.075

               O₂         :         MgO

                1          :           2

             0.1         :      2/1×0.1 = 0.2

Mass of magnesium oxide:

Mass = number of moles × molar mass

Mass = 0.075 mol × 40 g/mol

Mass = 3 g

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explanation:

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since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.