What is the pressure in a 29.0-L cylinder filled with 45.5 g of oxygen gas at a temperature of 325 K ?

P = 1.29 atm

Explanation:

Given data:

Volume of cylinder= 29.0 L

Mass of oxygen gas = 45.5 g

Temperature = 325 K

Pressure of gas = ?

Solution:

First of all we will calculate the number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 45.5 g/ 32 g/mol

Number of moles = 1.4 mol

Pressure of oxygen:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

P ×29.0 L = 1.4 mol × 0.0821 atm.L/ mol.K   × 325 K

P = 37.36 atm. L / 29.0 L

P = 1.29 atm

the dependant variable is spilled water

the independent is the heat

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