A balloon is inflated with helium to a volume of 45L at room temperature (298K). If the balloon is cooled to 200.K, what is the new volume of the balloon?

V₂ = 30.20 L

Explanation:

Given data:

Initial volume = 45 L

Initial temperature = 298 K

Final temperature = 200 K

Final volume = ?

Solution;

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 45 L × 200 K / 298 k

V₂ = 9000 L.K / 298 K

V₂ = 30.20 L

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .