Consider the production of sulfur trioxide from sulfur dioxide and oxygen gas:How many grams of sulfur dioxide reacted if 163 kilojoules of heat were evolved in an experiment

102.4 g

Explanation:

The equation of the reaction is;

2SO2(g) + O2(g) > 2SO3(g) ΔH = -198 KJ/mol

Now, given that;

If 2 moles of SO2 evolves 198 KJ/mol of heat

x moles of SO2 evolves 163 KJ/mol of heat

x = 2 * 163/198

x = 1.6 moles of SO2

molar mass of SO2 = 64 g/mol

mass of SO2 = 1.6 moles * 64 g/mol = 102.4 g

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answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.