A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. How much aluminum sulfate is produced? 2A1() + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

A. 7.92 g Al2(SO4)3
B. 4.42 g Al2(SO4)3
C. 1.3 g Al2(SO4)3
D. 2.34 g Al2(SO4)3

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

c

explanation: