The compound cisplatin, Pt(NH3)2Cl2, has been studied extensively as an antitumor agent.___K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH3)2Cl2 (s) + ___KCl (aq)What mass of cisplatin can be made from 200 g of K2PtCl4

Mass of cisplatin can be made : 144.6 g

Given

Reaction(unbalanced)

K2PtCl4 (aq) + ___NH3 (aq)  ___Pt(NH3)2Cl2 (s) + ___KCl (aq)

200 g of K2PtCl4

Required

mass of cisplatin  Pt(NH3)2Cl2

Solution

Balanced equation

K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)

mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :

mol = mass : Mw

mol = 200 : 415

mol = 0.482

From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482

Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :

mass = mol x MW

mass = 0.482 x 300

mass = 144.6 g

the answer is c i believe