2.00 L of 18.5 M H2SO4, concentrated sulfuric acid Q. 2 Calculate the number of moles and the mass of the solute in each of the following

Mass = 3626 g

Number of moles = 37 mol

Explanation:

Given data:

Volume of solution = 2.00 L

Molarity of solution = 18.5 M

Number of moles of solute  = ?

Mass of solute = ?

Solution:

Molarity = number of moles / volume in L

By putting values,

18.5 M = number of moles / 2.00 L

Number of moles = 18.5 M × 2 L

Number of moles = 37 mol

Mass of solute:

Mass = number of mole × molar mass

Mass = 37 mol × 98 g/mol

Mass = 3626 g