A sample of chlorine gas has a volume of 6500 ml at STP. What will the volume be if the temperature is increased to 50.°C and the pressure is decreased to 0.25 atm?

The volume will be 30759mL

Explanation:

To solve this question we need to use the combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas

Computing the values (STP are 1atm and 273.15K):4

P₁ = 1atm

V = 6500mL

T₁ = 273.15K

P₂ = 0.25atm

V₂ = ?

T₂ = 273.15K + 50°C = 323.15K

1atm*6500mL/273.15K = 0.25atmV₂/323.15K

V₂ = 30759mL

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