Calculate the percent by mass of C in NaHCO3 if an 84.0 g sample contains: 23.0 g of Na, 1.0 g of H, 12.0 g of C, and 48.0 g of O. (ONLY TYPE THE NUMBER NOT THE UNIT)

43.452

step-by-step explanation:

284 times .153 = 43.452

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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