For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side? reactants: 1; products: 1
reactants: 1; products: 2
reactants: 2; products: 1
reactants: 2; products: 2

The balanced chemical reaction is written as follows:

bacl2 + na2so4 → baso4 + 2nacl

Therefore, the number of chlorine atoms in the reactants side and the products side would be 2 atoms in both sides which should be the case because the number of atoms in each side should have the same number.

Explanation:

Internet

girl imma just put my comment here because i need a couple point okurrttt