Determine the mass of 21.05 moles of iron(III) sulfide.

The mass of 21.05 moles of iron(III) sulfide is 4,372.085 grams.

Explanation:

Iron (III) sulfide is a chemical compound with the formula Fe₂S₃.

Being the molar mass of the elements:

then the molar mass of iron sulfide (III) is:

Fe₂S₃= 2* 55.85 g/mole + 3* 32 g/mole=  207.7 g/mole

Molar mass is the amount of mass that a substance contains in one mole. Then the rule of three can be applied: if in 1 mole of iron (III) sulfide there are 207.7 grams, in 21.05 moles how much mass is there?

mass= 4,372.085 grams

The mass of 21.05 moles of iron(III) sulfide is 4,372.085 grams.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

a chemical reaction

explanation: