At what temperature will 5 g of Cl2 exert a pressure of 900 mmHg at a volume of .75 L?

The temperature : 154.73 K

Given

mass = m = 5 g of Cl2

P = 900 mmHg = 1,18421 atm

V = 0.75 L

Required

Temperature

Solution

mol Cl2 = mass : MW = 5 : 71 = 0.07

Ideal gas law : PV = nRT

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 L.atm / mol K  

T = temperature, Kelvin  

T = PV/nR

Input the value :

T = 1.18421 x 0.75 / 0.07 x 0.082

T = 154.73 K

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.