For all seawater problems, assume the salinity is 3.5% If you have a 2000 gram sample of seawater, how many grams of pure water are there?
0.035 x 2000) = x, 2000 - x = pure water
Answer to the nearest WHOLE number.

1930g

Explanation:

We have been given that the salinity of sea water is 3.5%;

  Now the mass of sea water sample is 2000g

So, problem here is to find the quantity of pure water in the sample = ?

Solution:

Let us find the quantity of the salt in the sample;

       Salt content  = 3.5% x 2000  = 70g

Amount of pure water  = 2000 - 70 = 1930g

the answer is 1 i believe