A. A student was given an unknown sample of a pure metal to identify. Its mass was 116 g. He determined that 511 J of energy raised the temperature of the sample from 21.6°C
to 40.5°C. Based on his measurements, what kind of metal was the sample? (4 points)

Silver

Explanation:

Given parameters:

Mass = 116g

Energy  = 511J

Initial temperature  = 21.6°C

Final temperature  = 40.5°C

Unknown:

Specific heat capacity and the type of metal = ?

Solution:

To solve this problem, we need to find the specific heat capacity of the metal given,

         H  = m x c x Ф  

H is the energy

m is the mass

c is the specific heat capacity

Ф is the change in temperature

        511  = 116 x c x (40.5 - 21.6)

         511  = 2192.4c

           c  = 0.233J/g°C

The specific heat capacity of silver is similar to this.

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.