ScF2 +
KBr >
KE +
ScBr2

Balanced equation :

ScF₂ + 2KBr ⇒ 2KF + ScBr₂

Given

Reaction

ScF₂ + KBr ⇒ KF + ScBr₂

Required

Balanced equation

Solution

1. Give coefficient

ScF₂ + aKBr ⇒ bKF + cScBr₂

Sc, left=1, right=c⇒c=1

F, left=2, right=b⇒b=2

K, left=a, right=b⇒a=b⇒a=2

The equation becomes :

ScF₂ + 2KBr ⇒ 2KF + ScBr₂

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.