How are the electron structures of boron (B) and aluminum (Al) similar? A. They both have valence electrons in the second energy level.
B. They both have 3 electrons in each sublevel.
C. They both have 1 electron in a p orbital.
D. The highest sublevel that has electrons is the 3p sublevel.
my brain isn't functioning correctly. 2 days up working on homework lol

C: They both have 1 electron in a p orbital.

Explanation:

Find the electron configuration of B

Boron is 1s 2s2 2p1

Find the electron configuration of Al

Aluminum is 1s2 2s2 2p6 3s2 2p1

If you look at the p orbital, they both have 1 electron.

Therefore, the correct answer is C.

Hope it helped!

no

explanation:

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part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years