If a sample contains 22 moles of CsPO4, what is the mass of that sample?

Mass = 5013.36 g

Explanation:

Given data:

Number of moles of CsPO₄ = 22 mol

Mass of sample = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of CsPO₄ = 132.91×1 + 30.97×1 +16×4 = 227.88 g/mol

by putting values,

Mass = 22 mol ×  227.88 g/mol

Mass = 5013.36 g

the answer to your question is c

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally