What is the volume of C2H2 produced when 45g of water reacts completely with calcium carbide

The volume of C₂H₂ : 28 L

Given

45g of water

Required

The volume of C₂H₂

Solution

Reaction

CaC₂(s) + 2 H₂O(l) ⇒ C₂H₂(g) + Ca(OH)₂(aq)

mol of water (MW = 18 g/mol) :

mol = mass : MW

mol = 45 g : 18 g/mol

mol = 2.5

From equation, mol ratio H₂O : C₂H₂ = 2 : 1, so mol C₂H₂ :

= 0.5 x mol H₂O

= 0.5 x 2.5

= 1.25

The volume of C₂H₂(assume at STP, 1 mol = 22.4 L) :

=1.25 mol x 22.4 L

=28 L

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.