A solution with a molarity of 0.1850 contains 19.30 grams of BaCl2. What is the volume of the solution

Volume in L = 0.50 L

Explanation:

Given data:

Molarity of solution = 0.1850 M

Mass of BaCl₂ = 19.30 g

Volume of solution = ?

Solution:

First of all we will calculate the number of moles of solute:

Number of moles = mass/molar mass

Molar mass of BaCl₂ = 208.23 g/mol

Number of moles = 19.30 g / 208.23 g/mol

Number of moles = 0.093 mol

Volume of solution:

Molarity = number of moles of solute / volume of solution in L

0.1850 M = 0.093 mol / Volume in L

Volume in L = 0.093 mol / 0.1850 M  (M= mol/L)

Volume in L = 0.50 L

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