According to the following reaction, how many moles of phosphorus trichloride will be formed upon the complete reaction of 25.4 grams of phosphorus (P_4) with excess chlorine gas? phosphorus (P_4) (s) - chlorine (g) --> phosphorus trichloride (l)
moles phosphorus trichloride

0.82 mole of PCl₃

Explanation:

We'll begin by calculating the number of mole in 25.4 g of P₄. This can be obtained as follow:

Mass of P₄ = 25.4 g

Molar mass of P₄ = 4 × 31 = 124 g/mol

Mole of P₄ =?

Mole = mass / Molar mass

Mole of P₄ = 25.4 / 124

Mole of P₄ = 0.205 mole

Next, the balanced equation for the reaction. This is illustrated below:

P₄ + 6Cl₂ —> 4PCl₃

From the balanced equation above,

1 mole of P₄ reacted to produce 4 moles of PCl₃

Finally, we shall determine the number of mole of phosphorus trichloride, PCl₃, produced by the reaction of 25.4 g (i.e 0.205 mole) of P₄. This can be obtained as follow:

From the balanced equation above,

1 mole of P₄ reacted to produce 4 moles of PCl₃.

Therefore, 0.205 mole of P₄ will react to produce = 0.205 × 4 = 0.82 mole of PCl₃

Thus, 0.82 mole of PCl₃ was obtained from the reaction.

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