What is the volume of which 0.25 mole of a gas occupied at 0.5 atm and 50°C ?

The volume of the gas : V = 13.243 L

Given

n = 0.25 mole

P = 0.5 atm

T = 50 + 273 = 323 K

Required

The volume

Solution

Ideal gas law

PV=nRT

R = gas constant = 0.082 L.atm/mol K

V = nRT/P

Input the value :

V=0.25 x 0.082 x 323 / 0.5

V = 13.243 L

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